(iii)
The probability that getting a difference of $1$,
Favorable outcomes $=(1,2),(2,1),(2,3),(3,2),(3,4),(4,3),(4,5),(5,4),(5,6),(6,5)$
Number of favorable outcomes $=10$
P(getting a sum of $6$) = Number of favorable outcomes/total number of Outcomes
$=10/36$
$=5/18$