(i) F = {(a, 3), (b, 2), (c, 1)} (ii) F = {(a, 2), (b, 1), (c, 1)}
solution:
(I) F = {(a, 3), (b, 2), (c, 1)} F(a) = 3, F(b) = 2 and F(c) = 1
F-1 (3) = a, F-1 (2) = b and F (1) = c
F-1 = {(3, a), (2, b), (1, c)}
(ii) F = {(a, 2), (b, 1), (c, 1)}
Since component b and c have a similar picture 1 for example (b, 1), (c, 1). Accordingly, F isn’t one-one capacity.