f : A → B characterized by f(x) = (x-2)/(x-3) Let (x, y) ∈ A then, at that point
????(????) =
???? − 2
???? − 3
???????????? ????(????) =
???? − 2
???? − 3
For f(x) = f(y)
Once more, f(x) = (x-2)/(x-3)
or on the other hand y = f(x) = (x-2)/(x-3)
y = (x-2)/(x-3) y(x – 3) = x – 2 xy – 3y = x – 2 x(y – 1) = 3y – 2
or on the other hand x = (3y-2)/(y-1)
Presently, f((3y-2)/(y-1)) =
3????−2−2
????−1
3????−2−3
????−1
f(x) = y
Consequently, f is onto work.