Solution:
According to the question, Mass of ice = 10 g = 0.01 kg
Amount of absorbed heat energy is Q = 5460 J
We have to find the specific latent heat of fusion of ice.
We are given that the specific heat capacity of water = 4200 J kg-1 K-1
Using the expression of heat energy => Q = mc(change in temperature), we can write the expression for amount of heat energy required by 10 g (0.01 kg) of water at 00 C to raise its temperature by 500 C.
Therefore, Heat Energy = 0.01 × 4200 × 50 = 2100 J
Let the specific latent heat of fusion of ice be L Jg-1
Then using the other expression of heat energy, i.e., Q = mL + mc△t
Putting values in above equation, we get
=> 5460 J = 10 × L + 2100 J
Or, L = 3360 / 10
Therefore, L = 336 J g-1