Solution:-

Given :

P = ₹ $10,000$, r = $8$% p.a., t = $2\frac{1}{3}$ years

For the first year, t = 1 year

S.I. = (P × r × t)/$100$

= $(20,000 × 9 × 1)/100$

= ₹ $1,800$

A = P + S.I.

= $20,000 + 1,800$

= ₹ $21,800$

New principal is ₹ $21,800$.

For the second year, t = $1$ year, p = ₹ $21,800$

S.I. = (P × r × t)/$100$

= $(21,800 × 9 × 1)/100$

= ₹ $1,962$

A = P + S.I.

= $21,800 + 1,962$

= ₹ $23,762$

New principal is ₹ $23,762$

For the third year, t = $1/3$ year, p = ₹ $23,762$.

S.I. = (P × r × t)/$100$

= $(23,762 × 9 × 1)/(100 × 3)$

= ₹ $712.86$

A = P + S.I.

= $23,762 + 712.86$

= ₹ $24,474.86$

C.I. = Interest in first year + interest in second year + interest in third year

= ₹ $(1,800 + 1,962 + 712.86)$

= ₹ $4,474.86$

Solution:-

Given :

P = ₹ $25,000$, r = $8\frac{2}{5}%$ p.a. = 42/5, Time, t = $1\frac{1}{3}%$ years

For the first year, t = $1$ year

S.I. = (P × r × t)/$100$

= $(25,000 × 42 × 1)/(100 × 5)$

= ₹ $2,100$

A = P + S.I.

= $25,000 + 2,100$

= ₹ $27,100$

New principal is ₹ $27,100$.

For the second year, t = $1/3$ year, p = ₹ $27,100$

S.I. = (P × r × t)/$100$

= $(27,100 × 42 × 1)/(100 × 5 × 3)$

= ₹ $758.80$

A = P + S.I.

= $27,100 + 758.80$

= ₹ $27,858.80$

C.I. = Interest in first year + interest in second year

= ₹ $(2,100 + 758.80)$

= ₹ $2,858.80$