Solution:
(i) Given:
Δ ABC and Δ AMP are the two right triangles.
To prove :
ΔABC ∼ ΔAMP
Proof :
∠AMP = ∠B = 90o
∠MAP = ∠BAC (Vertically Opposite Angles)
⇒ ΔABC∼ΔAMP (AA similarity)
(ii) ΔABC∼ΔAMP
CA/ PA = BC/ MP (Corresponding sides are proportional)
Hence proved.