Solution:-
From the question, cos θ = .7258
In the table of cosines, look for a value (≤ .7258) which is sufficiently close to .7258.
We find the value .7254 occurs in the horizontal line beginning with 43o and in the column headed by 30’ and in the mean difference, we see .7258 – .7254 = .0004 in the column of 2’.
So we get, θ = 43o 30’ – 2’ = 43o 28’.
(i) θ = 43° 30′ – 2’
= 43° 28′.
(ii) 2 tan θ – sin θ
Substitute the value θ,
= 2 tan43°28′ – sin43°28′
= 2 (.9479) – .6879
= 1.8958 – .6879
= 1.2079
Therefore, the value of 2 tan θ – sin θ is 1.2079