Given G.P. is
How about we consider that
![\[n\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-f5a9f9f8ec465afafa9c7e5e61e0e006_l3.png "Rendered by QuickLaTeX.com")
terms of this G.P. be needed to acquire the amount of
![\[120.\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-56d5bd40789e8420b3f101b93c5e291a_l3.png "Rendered by QuickLaTeX.com")
We realize that,
Here,
![\[a\text{ }=\text{ }3\text{ }and\text{ }r\text{ }=\text{ }3\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-798ab0831cd540d4b1f3b0a2d0bd1493_l3.png "Rendered by QuickLaTeX.com")
Equating the types we get,
![\[n\text{ }=\text{ }4\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-a7752b5455a64229b78a748ad714831b_l3.png "Rendered by QuickLaTeX.com")
Hence, four terms of the given
![\[G.P.\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-1dadd4e95aec87cc3adfa3fd45c98025_l3.png "Rendered by QuickLaTeX.com")
are needed to acquire the total as
How many terms of G.P. 3, 32, 33, … are needed to give the sum 120?
How many terms of G.P. 3, 32, 33, … are needed to give the sum 120?