How many different products can be obtained by multiplying two or more of the numbers 3, 5, 7, 11 without repetition?

Answer : The given no. is 3,5,7,11.

The no. of different products when two or more is taking= the no. of ways of taking the product of two no.+ the no. of ways of taking the product of three no. + the no. of ways of taking the product of four no.

= 4C2 + 4C3 + 4C4

= 6 + 4 + 1

= 11