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Find the roots of the given equation:

\begin{array}{l} 48 x^{2}-13 x-1=0 \\ \Rightarrow 48 x^{2}-(16 x-3 x)-1=0 \\ \Rightarrow 48 x^{2}-16 x+3 x-1=0 \\ \Rightarrow 16 x(3 x-1)+1(3 x-1)=0 \\ \Rightarrow(16 x+1)(3 x-1)=0 \\ \Rightarrow 16 x+1=0 \text { or } 3 x-1=0 \\ \Rightarrow x=\frac{-1}{16} \text { or } x=\frac{1}{3} \end{array}

Hence, the roots of the equation are and .