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Home » Find the maximum value of 2x ^3 – 24x + 107 in the interval [1, 3]. Find the maximum value of the same function in [–3, –1].
Find the maximum value of 2x ^3 – 24x + 107 in the interval [1, 3]. Find the maximum value of the same function in [–3, –1].
Applications of Derivatives | CBSE | Class 12 | Exercise 6.5 | Maths | NCERT
Find the maximum value of 2x ^3 – 24x + 107 in the interval [1, 3]. Find the maximum value of the same function in [–3, –1].

Let 

 

Now 

 

 

 

  or   [Turning points]

For Interval [1, 3],  is turning point.

At  

At  

At  

Therefore, maximum value of  is 89.

For Interval    is turning point.

At  

At  

At  

Therefore, maximum value of  is 139.

i

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