(i)
In ∆ ABC,
DE ∥ BC.
Applying Thales’ theorem,
∵ AD = 3.6 cm , AB = 10 cm, AE = 4.5cm
∴ DB = 10 − 3.6 = 6.4cm
(ii)
In ∆ ABC,
DE || BC
Applying Thales’ Theorem,
Add 1 to both sides,
(i)
In ∆ ABC,
DE ∥ BC.
Applying Thales’ theorem,
∵ AD = 3.6 cm , AB = 10 cm, AE = 4.5cm
∴ DB = 10 − 3.6 = 6.4cm
(ii)
In ∆ ABC,
DE || BC
Applying Thales’ Theorem,
Add 1 to both sides,