Because of the – R impact of the benzene ring, aromatic amines have lower availability of N atoms. As a result, the electrons on the N – atom in aromatic amines are difficult to transfer. As a...
(i) protonation of amines gives amide ion. Similarly, alcohol gives away a proton which results in alkoxide ions. In an amide ion, the negative charge is on the N-atom, whereas in an alkoxide ion,...
(i) When aromatic amine reacts with nitrous acid (which is generated in situ from NaNO2) and a mineral acid like phosphoric acid, it produces nitrous oxide. (ii) When aliphatic primary amines react...
The Gabriel phthalimide synthesis is most commonly employed to make aliphatic primary amines. Nucleophilic substitution (SN2) of alkyl halides by the anion generated by the phthalimide is an example...
(i) (ii) (iii) Answer: (i) (ii) (iii)
(i) (ii) Answer: (i) (ii)
Compound ‘C,' with the molecular formula C6H7N, is created by heating compound ‘B' with Br2 and KOH, according to the formula. This is a decomposition of Hoffmann bromamide. As a result, compound B...
(i) (ii) Answer: (i) (ii)
(i) (ii) Answer: (i) (ii)
(i) (ii)
(i) Benzoic acid to aniline <br>(ii) Aniline to 2, 4 ,6 – tribromofluorobenzene (i) (ii)
(i) When an alkyl or benzyl halide reacts with an ethanolic solution of ammonia, the halogen atom is replaced by an amino ( – NH2) group in a nucleophilic substitution process. Ammonolysis is the...
(i) A primary amine with one carbon atom less than the original amide is formed when an amide is treated with bromine in an aqueous or ethanolic solution of sodium hydroxide. The Hoffmann bromamide...
(i) The carbylamine reaction is a test for determining the presence of primary amines. Carbylamines (or isocyanides) are produced d when aliphatic and aromatic primary amines are heated with...
Hinsberg's test can be used to identify and discriminate primary, secondary, and tertiary amines. The amines are allowed to react with Hinsberg's reagent, benzene sulphonyl chloride(C6H5SO2 Cl)....
(i) (ii)
(i) (ii)
(i) (ii)
(i) Ethanoic acid into methanamine (ii) Hexanenitrile into 1–aminopentane
![\[{{\mathbf{C}}_{\mathbf{2}}}{{\mathbf{H}}_{\mathbf{5}}}\mathbf{N}{{\mathbf{H}}_{\mathbf{2}}},\text{ }{{\left( {{\mathbf{C}}_{\mathbf{2}}}{{\mathbf{H}}_{\mathbf{5}}} \right)}_{\mathbf{2}}}\mathbf{NH},\text{ }{{\left( {{\mathbf{C}}_{\mathbf{2}}}{{\mathbf{H}}_{\mathbf{5}}} \right)}_{\mathbf{3}}}\mathbf{N}\text{ }\mathbf{and}\text{ }\mathbf{N}{{\mathbf{H}}_{\mathbf{3}}}\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-7543ab20599101d93b093dbe8157db71_l3.png "Rendered by QuickLaTeX.com")
![\[{{\mathbf{C}}_{\mathbf{2}}}{{\mathbf{H}}_{\mathbf{5}}}\mathbf{OH},\text{ }{{\left( \mathbf{C}{{\mathbf{H}}_{\mathbf{3}}} \right)}_{\mathbf{2}}}\mathbf{NH},\text{ }{{\mathbf{C}}_{\mathbf{2}}}{{\mathbf{H}}_{\mathbf{5}}}\mathbf{N}{{\mathbf{H}}_{\mathbf{2}}}\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-7401558baa4042733e47b502dc9be068_l3.png "Rendered by QuickLaTeX.com")
![\[{{\mathbf{C}}_{\mathbf{6}}}{{\mathbf{H}}_{\mathbf{5}}}\mathbf{N}{{\mathbf{H}}_{\mathbf{2}}},\text{ }{{\left( {{\mathbf{C}}_{\mathbf{2}}}{{\mathbf{H}}_{\mathbf{5}}} \right)}_{\mathbf{2}}}\mathbf{NH},\text{ }{{\mathbf{C}}_{\mathbf{2}}}{{\mathbf{H}}_{\mathbf{5}}}\mathbf{N}{{\mathbf{H}}_{\mathbf{2}}}\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-ca2c31e232cd6bffda273a89d9fc4d7d_l3.png "Rendered by QuickLaTeX.com")
(i) There is no solvation effect in the gas phase. As a result, the + I impact is primarily responsible for the fundamental strength. The firmer the base, the larger the +I impact. In addition, the...
![\[\left( \mathbf{b} \right)\text{ }{{\mathbf{C}}_{\mathbf{6}}}{{\mathbf{H}}_{\mathbf{5}}}\mathbf{N}{{\mathbf{H}}_{\mathbf{2}}},\text{ }{{\mathbf{C}}_{\mathbf{6}}}{{\mathbf{H}}_{\mathbf{5}}}\mathbf{NHC}{{\mathbf{H}}_{\mathbf{3}}},\text{ }{{\mathbf{C}}_{\mathbf{6}}}{{\mathbf{H}}_{\mathbf{5}}}\mathbf{C}{{\mathbf{H}}_{\mathbf{2}}}\mathbf{N}{{\mathbf{H}}_{\mathbf{2}}}.\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-c77fbba6b41e37702bf58112d1373bda_l3.png "Rendered by QuickLaTeX.com")
(a) The presence of the electron-donating – CH3 group in p – toluidine boosts the electron density on the N-atom. As a result, p – toluidine has higher basicity than aniline. In the case of p...
(i) C2 H5 NH2 consists of one –C2 H5 group. (C2 H5 )2NH consists of two –C2 H5 groups. As a result, the +I effect in ( C2H5)2NH is greater than that in...
(i) Aniline does not undergo Friedel – Crafts reaction. In the presence of AlCl 3, the Friedel–Crafts reaction is carried out. However, we already know that AlCl 3 is acidic, whereas aniline is not....
(i) Methylamine in the water when made to react with ferric chloride, precipitates hydrated ferric oxide. Water is less basic than methylamine due to the presence of the – CH3 group and the + I...
(i) p Kb of aniline is more than that of methylamine.(ii) Ethylamine is soluble in water whereas aniline is not. (i) p Kb of methylamine is lesser than that of aniline : The electrons accessible on...
(i) Ethylamine and aniline (ii) Aniline and benzylamine(iii) Aniline and N-methylaniline. (i) azo–dye test can distinguish aniline & Ethylamine. When aromatic amines react...
(i) Methylamine and dimethylamine (ii) Secondary and tertiary amines\ (i) dimethylamine & Methylaminecan be made notable by the carbylamine test. When aliphatic and aromatic primary amines...
(i) N – Methyl benzamine or N – methylaniline ( 20 amine ) (ii) N – Ethyl – N – methyl ethanamine ( 30 amine ) (iii) 3 – Bromobenzenamine or 3 – bromoaniline ( 10 amine...
(i) CH3 NH CH ( CH3 )2 (i) ( CH3 )3 CNH 2 (i) N – Methyl – 2 – methyl ethanamine ( 20 amine ) (ii) 2 – Methylpropan – 2 – amine ( 10 amine...
(i) ( CH3 )2 CH NH 2 (ii) CH3 ( CH2 )2 NH 2