[Hint: Draw a line through Q and perpendicular to QP.] As per the inquiry, Digressions PQ and PR are attracted to a circle to such an extent that ∠RPQ = 30°. A harmony RS is attracted corresponding...
In a right triangle ABC in which ∠B = 90°, a circle is drawn with AB as diameter intersecting the hypotenuse AC and P. Prove that the tangent to the circle at P bisects BC.
As per the inquiry, In a right point ΔABC is which ∠B = 90°, a circle is drawn with AB as distance across meeting the hypotenuse AC at P. Likewise PQ is a digression at P To Prove: PQ separates BC...
Two circles with centres O and O‘ of radii 3 cm and 4 cm, respectively intersect at two points P and Q such that OP and O‘P are tangents to the two circles. Find the length of the common chord PQ.
As per the inquiry, Two circles with focuses O and O' of radii 3 cm and 4 cm, individually meet at two focuses P and Q, to such an extent that OP and O'P are digressions to the two circles and PQ is...
If AB is a chord of a circle with centre O, AOC is a diameter and AT is the tangent at A as shown in Fig. 9.17. Prove that ∠BAT = ∠ACB
As per the inquiry, A circle with focus O and AC as a measurement and AB and BC as two harmonies additionally AT is a digression at point A To Prove : ∠BAT = ∠ACB Verification : ∠ABC = 90° [Angle in...
From an external point P, two tangents, PA and PB are drawn to a circle with centre O. At one point E on the circle tangent is drawn which intersects PA and PB at C and D, respectively. If PA = 10 cm, find the perimeter of the triangle PCD.
As per the inquiry, From an outside point P, two digressions, PA and PB are attracted to a circle with focus O. At a point E on the circle digression is drawn which crosses PA and PB at C and D,...
Let s denote the semi-perimeter of a triangle ABC in which BC = a, CA = b, AB = c. If a circle touches the sides BC, CA, AB at D, E, F, respectively, prove that BD = s – b.
As indicated by the inquiry, A triangle ABC with BC = a , CA = b and AB = c . Likewise, a circle is engraved which contacts the sides BC, CA and AB at D, E and F individually and s is semi-border of...
If a hexagon ABCDEF circumscribe a circle, prove that AB + CD + EF = BC + DE + FA.
As per the inquiry, A Hexagon ABCDEF encompass a circle. To demonstrate: Stomach muscle + CD + EF = BC + DE + FA Verification: Digressions drawn from an outside highlight a circle are equivalent....