Effective resistance = 1/R + 1/R = 2/R Current, I = V/(R/2) = 0.6A V/R = 0.3A switch is closed, Effective Resistance = Re 1/Re = 1/R + 1/R + 1/R = 3/R Re = R/3 Therefore, final current, I = V/(R/3)...
answer: Total current = I = I1 + I2 + I3 from ohms law I = V/R, I1 = V/R1 I2 = V/R2 I3 = V/R3 V/R = V/R1 + V/R2 + V/R3 1/R = 1/R1 + 1/R2 + 1/R3
Answer: i) Total resistance = R Given, R1 = 5 ohms R2 = 3+2 = 5 ohms 1/R = 1/5 + 1/5 R = 2.5 ohms ii) Current flowing through the circuit, I = V/R = 1.6 amps
Answer: The above circuit shows resistances R1 and R2 connected in series with a battery of V volts Total current = I = I1 + I2 apply ohms law, I=V/R I1 = V/R1 I2 = V/R2 V/R = V/R1 + V/R2 1/R = 1/R1...
c) B can be used in the making of the heating elements of an electric iron because the resistivity of B is the highest . d) C and E are the two substances that should be used for making electric...
Answer: a) E is the best conductor of electricity because it has the least resistivity . b) C is a better conductor between A and C because the resistivity of C is lesser than that of A .
Answer: Effective resistance = R 1/R = 1/R1 + 1/R2 + 1/R3 1/R=1/30 + 1/10 +1/5 R=3 ohm
Answer : c) Insulator is B = 1.0×1010 Ωm . d) Semiconductor is D = 2.3×103 Ωm .
Answer: A parallel circuit is a circuit in which the electricity travels over numerous separate pathways. i) Current through R1=6/5 = 1.2A Current through R2 =6/10= 0.6A Current through R3 =6/30=...
Answer: a) Good conductor is C = 10.0×10-8 Ωm . b) Resistor is A = 110×10-8 Ωm .
Answer: d) one-fourth is the correct answer. We know p=v²/R where R is constant p turns 1/4 times when V is halved The electric power is one-fourth of the actual value when the potential difference...
Answer : c) For making of the solar cells, P = 2.3×103 Ωm can be used because this materials is a semiconductor .
Answer: c) 293 is the correct answer. When all 293 bulbs are linked in parallel and have 75W and 220V, a total of 293 bulbs can be used.
Answer: The resistances R1,R2 and R3 are linked in series with a V volt battery in the circuit above. Let V1 be the potential difference between R1 and V2 be the potential difference between R2....
Answer: a) For making of the electric wires, Q = 2.63×10-8 Ωm can be used because this material has a very low resistivity b) For making of the handle for soldering iron, R = 1.0×1015 Ωm can be used...
Answer: d) 3 J/s is the correct answer. Electrical energy transfered per second , E=VIt=6 x 0.5 x 1 When a light with a voltage of 6V and a current of 0.5A is utilised, 3 J/s of electrical energy is...
Answer: d) 15A is the correct answer. Current drawn by the kettle, I=P/V = 3000/230 So the cable should be able to carry more current than this and hence the answer is 15 A. An electric kettle with...
Answer: d) 6000J is the correct answer. According to the question, Power= 100 W Time, t = 1 minute = 60 seconds P=W/t W=6000J Energy is the ability to do work. Hence, In one minute, 6000J of energy...
Answer: given V=6V, Current through 5 ohm resistor =V/R= 2A i) V = IR R = 3 ohm ii) V = 10 + 6 = 16V
Answer: We know that, R = ρl/A Given that, l’ = 2l A’ = A/2 And ρ’ = ρ (as the material of the wire is the same) Therefore, R’ = ρ’l’/A’ = ρ2l/(A/2) = 4ρl/A = 4R Therefore, R’ = 4×20 =...
Answer: c) Kilowatt-hour is the right answer. The commercial unit of energy is the kilowatt hour.
Answer: a) Joule is the correct answer. The joule is the SI unit of energy.
Answer: The correct option is b) 2 times. Reason: As, R = ρl/A so R' = ρl/(A/2) = 2ρl/A ⇒R' = 2R So , new resistance becomes 2 times the original resistance .
Answer: i) Current through 5 ohm resistor =V/R= 2A ii) Current through R = 2A because 5 ohm resistor and R are connected in series
Answer: b) Rupees 24 is the correct answer. It is assumed that the cost of electrical energy is rupees 4 per kWh. The duration of the event is 3 hours. The electric heater has a 2kW output. We can...
Answer: b) 850W is the proper option. The electric irons we use in our homes have a power rating of 850W.
Answer: d) Watt is the correct answer. The watt is the unit of measurement for electric power.
Answer: b) 6W is the correct option P = VI is the formula for calculating power Substituting the values of V and I, we get P = 6W.
Answer: The resistances R1 and R2 are linked in series with a V volt battery in the circuit above. Let V1 be the potential difference between R1 and V2 be the potential difference between R2. ...
Answer: The correct option is c) Temperature . Reason : The resistivity or specific resistance of a material is an intensive property (property which does not depend on the system size or the amount...
Answer: c) One kilowatt hour is the amount of energy utilised by an electrical equipment with a power of one kilowatt for one hour. d) Given in the question, P = 500W = 0.5kW T = 20 hour Thus,...
Answer: The correct option is b) half Reason: Resistance is inversaly proportional to (A) Area (cross sectionsl area of conductor) . R∝ 1/A So when A Doubled then Resistance became half .
Answer: Total current flowing through circuit, I = 6A R1 = 3 Ω R2 = 6 Ω Combined resistance R is 1/R = 1/3 + 1/6 = 3/6 R = 2 Ω Potential difference across the combined resistance = IR = 12V...
Answer: Total current flowing through circuit, I = 6A R1 = 3 Ω R2 = 6 Ω Combined resistance R is 1/R = 1/3 + 1/6 = 3/6 R = 2 Ω Potential difference across the combined resistance = IR = 12V a)...
Answer: a) The rate at which electrical energy is consumed is referred to as electric power. It is given as: P = VI = watt b) Given in the question, V =...
Answer: The correct option is d) A semiconductor . Reason : The resistivity of a certain material is 0.6 Ωm. The material is most likely to be a semiconductor because it has moderate...
answer: Given that Total current flowing through circuit, I = 6A R1 = 3 Ω R2 = 6 Ω a) Combined resistance R is 1/R = 1/3 + 1/6 = 3/6 R = 2 Ω b) Potential difference across the combined resistance =...
Answer: The correct option is a) four times. Reason : Resistance of the wire is given by: R = ρ lA When the diameter is halved: d'=d2 Radius: r'=r2 Area of cross-section: A'=πr'2=πr22=πr24=A4 Area...
Effective resistance = R1+R2=20 + 20 = 40 ohms a) Current flowing through the circuit = I = V/R = 5/40 = 0.125amp b) Potential difference across each resistance = IR = 2.5V
Answer: a) b) Effective resistance = R1+R2=20 + 20 = 40 ohms
Answer: Given in the question, V = 230V I = 0.4amp We have to find the rate at which electrical energy is transferred i.e., Power We know that, P = VI Substituting the values of V & I, we get P...
Answer: Given, V = 6V R1 = 2Ω R2 = 3 Ω Effective resistance = R 1/R = ½ + 1/3 1/R = 5/6 R = 1.2 Ω Current flowing through battery, I = V/R = 6/1.2 = 5A
Answer: Given in the question, I = 13amp V = 230V We know that, P = VI Substituting the values of V & I, we get P = 2.99kW
answer: Given, V = 6V R1 = 2Ω R2 = 3 Ω a)Because of its lower resistance, 2 ohm resistance has a larger share of current. b) Effective resistance = R 1/R = ½ + 1/3 1/R = 5/6 R = 1.2...
Answer: The correct option is c) 60 Ω. Reason : If the resistance of a certain copper wire is 1 Ω, the resistance of a similar nichrome wire will be about 60 Ω because the resistivity of nichrome is...
Answer: Given, V = 6V R1 = 2Ω R2 = 3 Ω a) Resistors are connected in parallel b) The potential difference across each resistor is equivalent to...
Answer: In parallel, 4 and 2 coils are connected. As a result, the total resistance, R 1/R = ¼ + ½ = ¾ R = ¾ Ω Total current,, I = V/R = 3 Ω V/(4/3) = 3...
Answer: The correct option is d) 30Ω Reason : We know that R = ρl/A Substituting the values in the above equation we get 30Ω.
Answer: d) 7 (1/2) is the correct answer. When combining resistors, the series and parallel combination formula must be employed. A parallel combination of 6 and 2 resistors is used....
Answer: The correct option is d) one-fourth Reason: We know that R = ρl/A Therefore, when the diameter of the wire is doubled, the resistance becomes one-fourth of the actual value.
Answer: It is given for heater, P = 2kWh T = 4 hours Thus, Energy consumed will be E1, PT = 8kWh It is given for TV, P = 200 watt = 0.2kW T = 4 hours Thus, Energy consumed will be E2, PT = 0.8kWh...
Answer: c) 20 is the correct answer. The overall resistance acquired is equivalent to 20 since the resulting resistance generated from the resistors that are connected in series is connected with 40...
Answer: The correct option is d) 30Ω We know that R = ρl/A Substituting the values in the above equation we get 30Ω.
Answer: a) 9 is the correct answer. The overall resistance of the supplied circuit is calculated using a series and parallel combination once more.
e) Given in question : l = 1m , R = 26Ω r = d/2 = 0.3/2 = 0.15mm = 0.15×10-3m We know that, ρ = R×A/l ρ= 1.83×10-6Ωm .
c) Following are the differences between resistance and resistivity: Resistance is the property of the conductor whereas Resistivity is the property of the material used in the conductor . In a...
Answer: c) 1V is the correct answer. We know that V = IR equals the potential difference across a resistor. As a result of swapping the values, we get a potential difference of 3V across the...
Answer: b) The current at Y is greater than the current at Z is the correct answer
Answer: Given in the question, V = 230V I = 10amp a) We know that, P = VI Substituting the values of V & I, we get P = 2300 watt = 2300 J/s b) Also, energy consumed in one minute = PT = 138000...
Answer: Where V1 = 5.0, V2 = 10.0, and V3 = 15.0 is the correct answer. We can acquire the correct numbers for V1, V2, and V3 by using the formula V = IR and replacing the values in the...
Answer: a) Resistivity is defined as: ρ = R×A/l where,R is the resistance of the conductor, A is the cross-sectional area of the conductor and l is the length of the conductor. b) The SI unit of...
Answer: c) The amount of energy consumed by 40W lamp in 1 hour, E1 = PT = 40 watt-hour 1 watt-hour = 3.6kj Thus, E1 = 144kJ Energy consumed by 60 watt lamp in 1 hour, E2 = PT = 216kJ Total energy...
Answer: Given in question , l = 1.0m , R = 23 ohm , ρ = 1.84×10-6Ωm We have, R = ρl/A 23 = 1.84×10-6 × 1/A A = 8×10-8 m2
Answer: d) 25 is the correct answer. The ratio of the resistance and the resulting resistance achieved when the parts are linked in parallel is 25 when a resistance wire is cut into...
c) ρ = 3ρ R’ = 3ρl/A = 3R Therefore, resistance becomes 3 times.
Answer: We know that, R = ρl/A a) l becomes 3l R’ = ρ3l/A = 3R Therefore, resistance gets tripled b) d becomes 3d & R = ρl/A R = ρl/πr2 = ρl/π(d/2)2 R’ = R/9 Therefore, resistance becomes...
Answer: a) When a wire's resistance is changed, the cross-sectional area increases, lowering the resistance. b) When a wire's resistance is changed, the material's diameter is increased, lowering...
Answer: c) As the temperature is increased, the resistance will increase
Answer: Given in the question, Number of lamps = 2 P1 = 40W P2 = 60W V = 220V a) Circuit diagram is shown below, b) The voltage across both bulbs is the...
Answer: The following are the impacts on a metal wire's resistance when: a) The resistance will grow when the length is increased. As $R=\rho L/a$ i.e resistance is directly proportional to length...
Answer: Given, V = 6V R1 = 2 Ω R2 = 3 Ω Combined resistance, Rt = 2+3 = 5 Ω I = V/Rt = 10/5 = 2A a) Potential difference across 2 Ω resistor = IR1 = 4V b) Potential difference across 3 Ω resistor =...
Answer: Given, V = 6V R1 = 2 Ω R2 = 3 Ω a) resistance of combination , Rt = 2+3 = 5 Ω b) Current flowing I = V/Rt = 10/5 = 2A
Answer: Given, V = 6V R1 = 3 Ω R2 = 6 Ω Current via three resistors = V/R1 = 6/3 = 2A
Answer: Given, V = 6V R1 = 3 Ω R2 = 6 Ω a) Resistance in combination, 1/R = 1/R1 + 1/R2 = 1/3 + 1/6 = ½ R2 = 2 b) Current flowing in the main...
Answer: Given, V = 4V R1 = 6 Ω R2 = 2 Ω Combined resistance, R = R1 + R2 = 8 ohm Current flowing, I = V/R = 4/8 = 0.5 amp Difference in potential...
Answer: Given, V = 4V R1 = 6 Ω R2 = 2 Ω a) Combined resistance, R = R1 + R2 = 8 ohm b) Current flowing, I = V/R = 4/8 = 0.5 amp ...
Answer: a) Given in the question, V = 6V R1 = 1 ohm R2 = 2 ohm Thus, we get Equivalent resistance of R1 & R2 in series, R = R1 + R2 = 3 ohm Total current, I = V/R = 6/3 = 2amp Current through...
Answer: Given, V = 12V R1, R2, and R3 are linked in a series. Current through R1 = V/R1 = 12/5 = 2.4 A Current through R2 = V/R2 = 12/10 = 1.2 A Current through R3 = V/R3 =...
Answer: 1st case: TV set Given, P = 250W = 0.25kWh T = 1 hour Thus, we get Energy consumed, E = PT = 0.25kWh 2nd case: Toaster Given, P = 1200W = 1.2kW T = 10 min = 1/6 hour Thus, we get Energy...
Given, V = 12V R1, R2, and R3 are linked in a series. a) Current through R1 = V/R1 = 12/5 = 2.4 A Current through R2 = V/R2 = 12/10 = 1.2 A Current through R3 =...
Answer: Given in the question, I = 5amp V = 220V T = 2 hours We have to find P = ? E = ? We know that, P = VI Substituting the values of V & I, we get P = 1.1kW Also we know that, Energy...
Answer: a) R1 represents the equivalent resistance of 10 and 40 resistances: 1/R1 = 1/10 + 1/40 = 5/40 R1 = 8 Ω R2 is the equivalent resistance of 30 ohms, 20...
Answer: Given in the question that, P = 4kW V = 220V T = 2hours c) Energy consumed in two hours, E = PT Substituting the values of P & T, we get E = 8kWh d) Cost of 1kWh = Rupees 4.6 Total cost...
When coils A and B are utilised in parallel, the current drawn is: Total resistance is 1/R = 1/Ra + 1/Rb = 1/24 + 1/24 = 2/24 = 1/12 R = 12 ohms I = V/R = 220/12 = 18.33 amps
answer: given Ra = Rb = 24 ohm a) Current drawn when coil A is the only one used: I = V/Ra = 220/24 = 9.16 amps b) Current drawn in series when coils A and B are used: Total resistance, R = Ra + Rb...
Answer: given that I = 5 amp V = 220 V R = V/I = 220/5 = 44 ohm The resultant resistance must be less than 176 ohm. Therefore, the resistors are connected in parallel Let...
Answer: Given in the question that, P = 4kW V = 220V a) Current, I = ? We know that, P = VI Substituting the values of P & V, we get I = 16amp b) Resistance, R = ? We know that, P = I2R...
Given, 1 amp = I R = 5 ohm ohm ohm ohm o Because the resistors are linked in parallel and the voltage across them is the same, the potential difference across each resistor is the same....
V/R = total current flowing through circuit Where R stands for total resistance. I = 12/6 = 2 amp Difference in potential across R1 = R1I = 8V
Answer: It is given in the question that, V = 250V I = 0.4 amp a) We have to find P = ? We know that, P = VI Substituting the values of V & I, we get P = 100 watt b) We have to find R = ? We...
answer: When two resistors are linked in parallel, the total resistance is 1/3 + 1/6 = 1/R' 3/6 = 1/R' R' is equal to 2 ohms. Total circuit resistance = 2 + 4 = 6...
Answer: 1st case, Power, P1 = 60W Number, n1 = 2 Time for use, T1 = 4 hours everyday Energy consumed, E1 = n1 × P1 × T1 E1 = 2 × 60 × 4 = 480watt-hour = 0.48kWh As a result, total energy consumed...
answer: a) When the two resistors are linked in series, the current through the resistors is kept to a minimum. The current flow is greatest when the resistors are linked in parallel. b) If the...
a) The relation between electric charge, time, and electric current is given as: Current $=($charge moved$) /($time$)$ While work done = potential difference $\times$ charge moved Therefore, above...
answer: Assume the following circuit: V = 4V Total resistance in line 1 = R1 = 6 + 3 = 9 Ω Total resistance in line 2 = R2 = 12 + 3 = 15 Ω a) Current flowing...
Answer: It is given in the question that, V = 220V P = 2.2kW = 2200 watt T = 3 hours It is known to us that Energy consumed = PT = 6.6kWh We also know that, P = VI Thus we get, I = 10...
As we all know, resistance is the measurement of an electrical circuit's resistance to current flow. The current is measured with an ammeter, while the potential difference is measured with a...
A device used to measure the flow of electric current is known as an ammeter. An ammeter is always linked in series with the electric current being measured. The following diagram shows how to...
a) An electric current is defined as the flow of electric charges through a conductor where the flow of current is caused by the potential difference between two locations in the conductor. b) The...
a) A cell or a battery is used to sustain the potential difference across a conductor. b) Given, Potential difference $=10 \mathrm{~V}$, Current, I $=2 \mathrm{~A}$ Time taken, $t=60 \mathrm{~s}$ We...
Answer: a) It is given in the question that, R = 300 ohm I = 1 amp T = 1 hour P = I2R = 300W E = PT = 300 watt-hour b) It is given in the question that, R = 100 ohm I = 2 amp T = 1 hour P = I2R =...
a) Electrons and closed b) Amperes, ammeter, and series
Given, Time taken, $t=10 s$ Charge moved, $\mathrm{Q}=25 \mathrm{C}$ Energy delivered is work done $=200 \mathrm{~J}$ a) Potential difference $=($ work done $) /($ charge moved $)=(200) /(25)=8...
Answer: It is given in the question that, V = 220V I = 0.5A P = ? It is known to us that, P = VI P = 110 watt
Answer: a) To brighten the lights, turn the switch to the right, as the resistance lowers as the switch is turned to the right. As a result, the circuit's resistance will be reduced. b) To dim the...
Given, Potential difference $=12 \mathrm{~V}$ a) Potential difference = (work done)/(charge moved) Work done = Potential difference$\times$ charge moved Therefore, $12 \mathrm{~J}$ of electrical...
Answer: a) When the lamps are connected in a series, the lamps will stop lighting if one of the filaments breaks. Because the circuit is broken due to the broken lamp. b) When the lamps are...
Answer: When two bulbs are linked in parallel instead of series, they create more light. This occurs because the voltage difference between parallel combinations remains constant. However, in the...
Answer: c) B and A are connected in series. If B burns out, A will also burn out. C, on the other hand, remains the brightest as it is in parallel combination with the other two.
Given, Charge moved $=1.6 \times 10^{-19}$ coulombs Current, I $=1 \mathrm{~A}$ Time taken, $t=1 \mathrm{~s}$ We know that, $\text{I}=\text{Q}/\text{t}$ $1=\text{Q}/1$ $\text{Q}=1\text{C}$ We also...
A circuit diagram is a graphic that uses electric symbols to show the individual components in an electric circuit and how they are connected. A voltmeter, on the other hand, will have a higher...
a) Because the value of the current flowing through the circuit is constant, the resistance of an ammeter should be very low. b) A voltmeter's resistance should be quite high since the current...
c) Voltage is another word for potential difference.
The correct answer is a) An ammeter is connected in series in a circuit and a voltmeter is connected in paralle
Answer: a) Let us consider two wires with same length and diameter. Let these two wires be of copper metal and nichrome alloy. We know that the resistance of nichrome wire is 60 times more than...
The right option for measuring current unit is d) Ampere.
Answer: c) As the temperature rises, the material's resistance rises as well.
Difference in potential across AB = IR3 = 1 × 5 = 5V Between B and C, the equivalent resistance is 1/R’ = 1/R1 + 1/R2 = 1/10 + 1/15 = 5/30 R’ = 6Ω Total resistance...
Answer: Based on the circuit diagram above; a) The total current is 1 amp when I insert the parallel combination of resistances R1 and R2. The current flow through R1 is I1, while the current...
Answer: a) The resistance of a conductor is proportional to its length. The material's resistance diminishes as the length of the material rises, and vice versa. b) The resistance of a conductor is...
Answer: Because the resistance of a thick wire is lower than that of a thin wire, current flow will be easier in a thick wire than in a thin wire.
Answer: a) Two examples of substances that are good conductors of electricity are silver and copper. These two metals have free electrons that are available for conduction. b) Given in question : l...
Answer: c) Difference in potential across the bulb = IR1 = 0.25 20 = 5V d) Difference in potential across the resistance wire = IR2 = 0.25 4 = 1V
Answer: a) Following is the expression for the resistance of a metallic wire in terms of the resistivity: R = ρl/A Where, R is the resistance of the wire , ρ is the resistivity of the wire , A is...
Answer: a) Resistivity is defined as the characteristic property of a substance which is dependent on the nature of the substance and the temperature of the substance used in the conductor. It is...
Answer: Ohm, increases, increases, and decreases respectively .
a) given R1=20 , R2 =4, Total resistance of the circuit is given as: R = R1 + R2 = 20 + 4 = 24Ω b) We know that, V = IR Therefore, 6 = 24I I = 6/24 = 0.25amp
Given that, Current, I $=5 \mathrm{~A}$ Time taken, $t=1 \mathrm{~s}$ We already know that, $\text{I}=\text{Q}/\text{t}$ $\text{Q}=\text{I}\times \text{t}=5\times 1=5\text{C}$ Total number of...
Answer: a) Because it receives greater voltage than the other two, C will be the brightest of the three. However, as they are in a series combination, A and B will be equally brilliant. b) If C...
Answer: a) As the temperature drops, the material's resistance drops as well. b) The presence of impurities in a metal enhances the material's resistance.
Answer: Following has more resistance: a) A long piece of nichrome wire . b) A thin piece of nichrome wire .
Answer: a) b) By connecting the lamps in parallel, the lamp's brightness can be adjusted.
Answer: Electric iron and toaster coils are composed of an alloy rather than a pure metal for the following reasons: a) When compared to pure metal, an alloy's resistivity is higher. b) At high...
Answer: The correct answer is c) A and B are illuminated when S2 is open, and S1 is closed.
Answer: The following are the two reasons why nichrome alloy is utilised to make electrical device heating elements: a) Nichrome has a very high resistance. b) At high temperatures, nichrome does...
Given that, Potential difference $=230 \mathrm{~V}$ Current, I $=8 \mathrm{~A}$ a) $I=Q / t$ $8=\mathrm{Q} / 1$ $\mathrm{Q}=8 \times 1=8 \mathrm{C}$ Hence, the current is $8 \mathrm{C}$. b) We...
Answer: The correct option is b) if one lamp fails, the others remain lit. The current going through the bulbs is different when they are connected in parallel. As a result, even if one lamp burns...
Answer: Nickel, chromium, manganese, and iron are used to make nichrome alloys. Nichrome's resistivity is 60 times higher than copper's. It is utilised in the manufacture of the heating elements...
Answer: c) All of the lamps are linked together in a series combination. d)
Answer: The substance used to make the heating element of an electric iron is nichrome.
Answer: a) When it comes to household wiring, parallel circuits are preferable over series circuits. This is because when one of the electrical appliances fails, it affects the others. b) The bulbs...
Answer: Because copper and aluminium wires have low resistivities, they are employed for power transmission.
Given, Charge moved $=300 \mathrm{C}$ Time taken $=10$ mins Current $=?$ $\mathrm{I}=\mathrm{Q} / \mathrm{t}$ By substituting the values, we get $\mathrm{I}=0.5 \mathrm{~A}$ hence, the correct...
Answer: Between iron and mercury, iron is a better electrical conductor. Iron has a lower resistance than mercury, and we know resistance is inversely proportional to current. As a result, as...
Answer Given, R1 = 0.2 Ω R2 = 0.3 Ω R3 = 0.4 Ω R4 = 0.5 Ω R5 = 12 Ω V = 9V Therefore, the resultant resistance is given as: R = R1 + R2 + R3 + R4 + R5 = 0.2 + 0.3 + 0.4 + 0.5 + 12 = 13.4 Ω...
Given that, Current, I $=5 \mathrm{~A}$ Time taken, $t=10 \mathrm{~s}$ Charge moved, $Q=$ ? $\text{I}=\text{Q}/\text{t}$ $\text{Q}=\mid \times \text{t}$ $\text{Q}=50\text{C}$ hence, the correct...
Answer: The best conductor of electricity is silver metal. This is due to the fact that, in comparison to other metals, the electrons in silver metal are open for free mobility.
Answer: The resistance of a conductor is determined by the following factors: a) The conductor's length . b) The conductor's cross-section .al area c) The conductor's temperature . d) The type of...
Answer: When the configuration is parallel, the battery's current consumption is higher. Any problem in one bulb will not influence the other operation because the bulbs are in a parallel...
Answer: Following is the right answer: c) The most significant amount of light is produced in the circuit (i). The resistance in the circuit is minimal because only one bulb is used, resulting in...
Answer: The following are the correct answers: a) The lamps in the circuit (ii) are the dimmest. Because the bulbs are connected in series, lowering the voltage in the rotation. b) The lamps in the...
Answer: When two or more resistances are connected end to end in a series combination, the resistances are said to be connected in series. The sum of all individual resistances equals the sum of any...
Answer: When the length of the wire is twice, the resistance of the wire doubles. Because resistance is proportional to length, yet area of cross section is inversely related to resistance, this is...
Answer: The following are the right answers: c) When a parallel circuit is employed, the appliance's operation can be regulated by individual switches. d) When appliances are linked in parallel,...
Answer: The following are the correct answers: a) The circuit must be parallel to have an identical power supply line. b) Each bulb will have the highest voltage when the circuit is parallel.
Answer: Given in the question, I = 5A R = 100 ohm T = 2 hours It is known to us that, Energy consumed = P × T = I2RT Substituting the values, Energy consumed = 5kWh 1kWh = 3.6 × 106J Therefore we...
Answer: Given, R1 = 6Ω R2 = 4 Ω V = 24V The two resistances are linked in parallel, according to the circuit schematic. Therefore, Current across R1 = I1 = V/R1 = 24/6 = 4amp Current across R2 = I2...
Answer: As the thickness of the conductor is increased, the resistance of the conductor decreases. This is because: R = (ρl)/(A) Where,R is the resistance . l is the length of the conductor , A is...
Answer: The quantity of electrical energy consumed when a 1 watt electrical appliance is used for 1 hour is measured in watt-hours. 1 watt-hour = 3600 joules.
Answer: In a household circuit, different electrical appliances are linked in parallel because: a) The voltage distribution from the power supply line to each appliance is the same. b) Individual...
Given that R1 = 4Ω R2 = 4 Ω R3 = 3 Ω From the given circuit diagram, 1/R = 1/R1 + 1/R2 1/R = ¼ + ¼ R = 2 Ω Total resistance = R + R3 = 2 + 3 = 5 Ω
Answer: Conductor: mercury, aluminium, iron, metal coin . Resistor: manganin, nichrome . Insulator: rubber, polythene, wood, bakelite, paper, thermocol .
a) Given that R1 = 500Ω R2 = 1000Ω From the above circuit diagram, R = R1 + R2 = 500 + 1000 =1500Ω b) Given that R1 = 2Ω R2 = 2Ω From the given circuit diagram, 1/R = 1/R1 + 1/R2 1/R = ½ + ½...
Answer: The equation that connects watts, volts, and ampere is as follows: 1 watt = 1 volt × 1 ampere
Answer: The following are the differences between excellent conductors, resistors, and insulators: Good conductors are those materials that have a low or negligible electrical resistance. Conductors...
Answer: Given that each part's resistance is R/2 Let's call the resulting resistance R'. 1/R’ = 2/R + 2/R R’ = R/4
Answer: Given in the question, P = 920W V = 230V I = ? It is known to us that, P = VI 920 = 230I I = 920/230 I = 4A
When connecting residential electrical appliances in a circuit, a series configuration is not used since if one of the electrical appliances fails, it affects all of the others. In addition, the...
Answer: Another piece of information offered by the label is that the rate of energy consumption is 36J/s.
Answer: We are aware of this, P =V2/R R is constant V is doubled Therefore, P = 2(V2)/R P = 4V/R As a result, when the resistance is doubled, the power is multiplied by four.
Answer: The following is estimated when the resistance configuration from A is combined with the resistance arrangement from B: 1/R = 1/10 + 1/1000 = (100+1)/1000 R = 1000/101...
Answer: The circuit schematic below shows two 4V bulbs that are connected in parallel with 2V cells.
Answer: kWh stands for kilowatt-hour and is the commercial unit of electrical energy.
Answer: Electric power is measured in watts.
Answer: Electric power is measured in kilowatts, and electric energy is measured in kilowatt-hours.
Answer: The joule is the SI unit of electric energy, and the watt is the SI unit of electric power.
Answer: The relationship between potential difference and current is described by Ohm's law.
Answer: It is given in the question, V = 220V P = 100W R = ? We know that, R = V2/P R = 484 ohm
Answer: The kilowatt-hour is the commercial unit of electric energy.
Answer: a) If you join them in parallel, 1R = 14 + 14 = 2/4 = 1/2 As a result, R = 2 ohm. b) By joining them in a sequence, R = 4 + 4 = 8 As a result, R = 8 ohm.
Answer: given R1 = 2 Ohm R2 = 6 Ohm Let case 1 be parallel combination 1/R = 1/R1 + 1/R2 1/R = ½ + 1/6 = 4/6 R = 6/4 = 1.5 ohm Let case 2 be series combination R = R1 + R2 = 2+6 = 8...
Answer: When the following type of circuit is used: a) The exterior of the hotel will be decorated in a series manner. The exterior lights do not need the same voltage difference b) lighting the...
Answer: Given in question : Current, I = 5A Potential difference, V = 3V We know that, V = IR Therefore, 3 = 5 × R R = 3/5 = 0.6 Ohms
Answer: Because we know that power is inversely related to resistance, a 60 watt bulb has a larger electrical resistance than a 100 watt bulb.
Answer: The resultant resistance will be less than either of the individual resistances when the two resistances X and Y are coupled in parallel.
Answer: Given in question : Resistance, R = 20 Ohms Current, I = 2 amp We know that, V = IR Therefore, V = 2 × 20 = 40V
Answer: The two resistances of 2 ohms must be connected in parallel to produce an equivalent resistance of 1 ohm.
Answer: Given in question : Potential difference, V = 20V Resistance, R = 5 Ohms Current, I = ? We know that, V = IR 20 = I × 5 I = 20/5 = 4A
Answer: Given, R1 = R2 = R3 = 3Ω 1/R = 1/R1 + 1/R2 + 1/R3 = 1/3 + 1/3 + 1/3 = 3/3 = 1 Therefore, R = 1Ω
Answer: When the bulbs are connected in a parallel configuration, they continue to glow. This occurs because the electricity flow is not disrupted, and the voltage differential between the other...
Answer: The electrical energy required by an electrical equipment is determined by the following two factors: a) The appliance's usage time b) The appliance's power rating
Answer: Given in question : Potential difference = constant Also, we know that, V = IR I = V/R Given that V is constant, therefore, I will be proportional to 1/R. Therefore, when R is halved, I also...
Answer: The reciprocal of the combined resistance of a number of parallel resistances is equal to the total of the reciprocals of all the individual resistances, according to the law of parallel...
Answer: Because the number of electrons present in the thick wire is more than that of the thin wire, a thick wire of the same length and substance will have less electrical resistance.
Answer: All of the other bulbs stop glowing when the bulbs are joined in series. Because the electrical appliances work on a definite voltage difference and in the series combination, the voltage...
Answer: The cumulative resistance of any number of resistances connected in series equals the individual resistances, according to the law of series combination of resistances. R = R1 + R2 + R3 + R4...
Answer: The following are the factors that influence the strength of an electric current flowing through a conductor: a) The voltage (or potential difference) between the conductor's ends b) The...
Answer: In our homes, the lights are not connected in a series. They are linked in a parallel manner. The home's electric appliances are connected in parallel combinations to achieve the same...