Given: –
An initial salary that will be given = ₹26000
There will be an automatic increase of ₹250 per month from the very next month and
thereafter.
Hint: – In the given information the salaries he receives are in A.P.
Let the number of the month is n.
Initial salary = a = ₹26000
Increase in salary = common difference = d = ₹250
i. Salary for the 10th month,
n = 10,
Salary = a + (n – 1)×d
= 26000 + (10 – 1)×250
= 28250
∴ Salary for the 10th month = ₹28250
ii. Total earnings during the first year = sum off all salaries received per month.
Total earnings =
n2[2a+(n–1)d]Here n = 12.
Total earnings=
122[2×26000+11×250]= 6×(42000 + 2750)
= 268500
Total earnings during the first year = ₹268500