Answer : The question paper has two sets each containing 10 questions. So the student has to choose 8 from part A and 5 from part B.
⇒ choosing 8 questions from 10 of part A in 10C8
⇒ choosing 5 questions from 10 of part B in 10C5
⇒ by Multiplication principle, we get
= total no. of ways in which he can attempt the paper is 10C8 X10C5
= 11340 ways