An analysis of monthly wages paid to workers in two firms A and B, belonging to the same industry, gives the following results: (i) Which firm A or B pays larger amount as monthly wages? (ii) Which firm, A or B, shows greater variability in individual wages?
An analysis of monthly wages paid to workers in two firms A and B, belonging to the same industry, gives the following results: (i) Which firm A or B pays larger amount as monthly wages? (ii) Which firm, A or B, shows greater variability in individual wages?

Solution:-

(i) According to the  given table,

Mean monthly wages of firm A = Rs

    \[5253\]

and Number of wage earners =

    \[586\]

Then,

Total amount paid =

    \[586\text{ }\times \text{ }5253\]

= Rs

    \[3078258\]

Mean monthly wages of firm B = Rs

    \[5253\]

Number of wage earners =

    \[648\]

Then,

Total amount paid =

    \[648\text{ }\times \text{ }5253\]

= Rs

    \[34,03,944\]

therefore, firm B pays larger amount as monthly wages.

(ii) given Variance of firm A =

    \[100\]

So, standard deviation

    \[\left( \sigma  \right)=\text{ }\sqrt{100}\]

=

    \[10\]

Given Variance of firm B =

    \[121\]

Then,

Standard deviation

    \[\left( \sigma  \right)=\sqrt{121}\]

=

    \[11\]

Therefore, the standard deviation is more in case of Firm B that means in firm B there is greater variability in individual wages.