Answer:
The given figure is:
We can draw a few conclusions from this figure, which are as follows:
(i) BP = BQ
(ii) DR = DS
(iii) CR = CQ
(iv) AP = AS
Since the above drawn conclusions are tangents on the circle from points D, B, A, and C respectively.
When the LHS and RHS of the above equations are added together, we get,
DR+BP+AP+CR = DS+BQ+AS+CQ
On rearranging them we get,
(DR+CR) + (BP+AP) = (CQ+BQ) + (DS+AS)
On simplifying,
AD+BC= CD+AB