(i) ˄0m(NH4OH) + ˄0m(NH4Cl) – ˄0(HCl)
(ii) ˄0m(NH4Cl) + ˄0m(NaOH) – ˄0(NaCl)
(iii) ˄0m(NH4Cl) + ˄0m(NaCl) – ˄0(NaOH)
(iv) ˄0m(NaOH) + ˄0m(NaCl) – ˄0(NH4Cl)
Correct Answer: (ii) ˄0m(NH4Cl) + ˄0m(NaOH) – ˄0(NaCl)
Explanation: ˄0m(NH4OH) is equal to ˄0m(NH4Cl) + ˄0m(NaOH) – ˄0(NaCl)