(i) ˄0m(HCl) + ˄0m(NaOHl) – ˄0m(NaCl)
(ii) ˄0m(HNO3) + ˄0m(NaNO3) – ˄0m(NaOH)
(iii) ˄0m(HNO3) + ˄0m(NaOH) – ˄0m(NaNO3)
(iv) ˄0m(NH4OH) + ˄0m(HCl) – ˄0m(NH4Cl)
Correct Answers:
(i) ˄0m(HCl) + ˄0m(NaOHl) – ˄0m(NaCl)
(ii) ˄0m(HNO3) + ˄0m(NaNO3) – ˄0m(NaOH)
Explanation: According to the Kohlrausch law of independent migration of ions, ˄0m(H2O) is equal to ˄0m(HCl) + ˄0m(NaOHl) – ˄0m(NaCl) and ˄0m(HNO3) + ˄0m(NaNO3) – ˄0m(NaOH)